Question

In: Chemistry

Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the...

Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the following data were obtained. Titrant is 0.0421 M EDTA, 13.84 mL were used when an aliquot of the sample was at pH 13.0, 19.36 mL were used for an aliquot at pH 10.5.

Solutions

Expert Solution

1 mole of Ca2+ reacts with 1 mole of EDTA

moles of EDTA used = 0.0421 M x 13.84 ml

                                  = 0.583 mmol

So,

calcium content in sample = 0.583 mmol x 40.08 g/mol/0.1 L

                                           = 233.67 ppm (mg/L)

queen_honey_blossom answered 2 years ago
Next > < Previous

Related Solutions

Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the...
Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the following data were obtained. Titrant is 0.0505 M EDTA, 13.49 mL were used when an aliquot of the sample was at pH 13.0, 16.99 mL were used for an aliquot at pH 10.5.
?. C3) A 100.00 ml. water sample was titrated 20.50 mL of 0.150 M EDTA after...
?. C3) A 100.00 ml. water sample was titrated 20.50 mL of 0.150 M EDTA after pH adjustment and using Eriochrome black T indicator. Knowing that density of water sample equals to 1.10 g/mL. (Caco 00.09 amu). Calculate the total hardness of water as Cacos and accordingly classify
A 100.00 mL sample of hard water is to be titrated with 0.03498 M EDTA solution....
A 100.00 mL sample of hard water is to be titrated with 0.03498 M EDTA solution. A small amount of Mg<sup>2+</sup> (that required 2.52 mL of EDTA to titrate as a blank solution) is added to the hard water sample. This sample requires 17.89 mL of EDTA to reach the endpoint. How many moles of Ca<sup>2+</sup> are in the hard water? Express answer as a decimal, not an exponent.
A 236.4 mL sample of water contains 0.0294 g of NaCl. Calculate the concentration in ppm....
A 236.4 mL sample of water contains 0.0294 g of NaCl. Calculate the concentration in ppm. concentration = ___ ppm
You wish to determine the amount of lead in a drinking water sample (500mL). It is...
You wish to determine the amount of lead in a drinking water sample (500mL). It is possible that sulfate in the sample (as well as other ions) will produce a matrix effect that will compromise the analysis, so you use a standard addition calibration method. You transfer 15 mL of your sample into each of five 50 mL volumetric flasks. You add the following volumes of a 5 ppm lead standard to the 5 flasks : 0, 5, 10, 15,...
It is recommended that drinking water contain 1.6 ppm of fluoride. If the local reservoir has...
It is recommended that drinking water contain 1.6 ppm of fluoride. If the local reservoir has a diameter of 450.0 m and a depth of 10.0 m (V= Pi*r2 *h), how many grams of F should be added to the water in the reservoir to give the recommended concentration? If fluoride is provided by hydrogen hexafluorosilicate (H2SiF6), how many grams of H2SiF6 contain Fluoride?
What is the concentration of Ca2+ in ppm (mg/L) in cave water saturated with calcite (calcium...
What is the concentration of Ca2+ in ppm (mg/L) in cave water saturated with calcite (calcium carbonate, Ksp = 4.7 × 10-9)? Answer:2.7
In an experiment a student dissolves 0.138g of a triprotic acid in 100.00 mL of water...
In an experiment a student dissolves 0.138g of a triprotic acid in 100.00 mL of water to prepare a solution for titration. A 25.00mL aliquot of the acid solution reqiures 15.49 mL of .108 M NaOH solution to reach the equivalence point. Calculate the molar mass of acid.
A) Calculate the concentration in ppm and the molarity of Cd in a 2.00 mL sample...
A) Calculate the concentration in ppm and the molarity of Cd in a 2.00 mL sample which has been shown to contain 16.4 μg Cd. Assume the sample has a density of 1.00 g/mL.
A surface water sample of 50 ml was taken to determine the concentration of an organic...
A surface water sample of 50 ml was taken to determine the concentration of an organic pollutant in the sample. An organic solvent was used as extracting solvent. On analysis of both phases by GC-MS, the pollutant concentration (mass/vol based) in the organic phase was 5 times that found in the aqueous phase. If after the second extraction (each using 50ml fresh organic solvent) the concentration of pollutant in the organic phase was 18 ppm (mass basis), determine the initial...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT