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Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the...

Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the following data were obtained. Titrant is 0.0421 M EDTA, 13.84 mL were used when an aliquot of the sample was at pH 13.0, 19.36 mL were used for an aliquot at pH 10.5.

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Expert Solution

1 mole of Ca2+ reacts with 1 mole of EDTA

moles of EDTA used = 0.0421 M x 13.84 ml

                                  = 0.583 mmol

So,

calcium content in sample = 0.583 mmol x 40.08 g/mol/0.1 L

                                           = 233.67 ppm (mg/L)

queen_honey_blossom answered 3 years ago
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