In: Chemistry
In an experiment a student dissolves 0.138g of a triprotic acid in 100.00 mL of water to prepare a solution for titration. A 25.00mL aliquot of the acid solution reqiures 15.49 mL of .108 M NaOH solution to reach the equivalence point. Calculate the molar mass of acid.
No. of moles of solute = given mass / molar mass
molar mass = given mass / no. of moles of solute
So to calculate molar mass first you need to calculate no. of moles of acis & for that you need to calculate molarity of an acid.
by apply molarity equation: M1V1 = M2V2
NaOH = acid M1 = 0.108 M , V1 = 15.49 ml ,M2 = ? V2 = 25.00ml
0.108 M . 15.49 ml = M2 . 25.00 ml
0.108 M . 15.49 ml / 25.00 ml = M2
molarity of acid , M2 = 0.067 M
Molarity = no. of moles of solute / 0.1 L of solvent . ----- (i) (100 ml = 0.1 L )
no. of moles of solute = molarity * volume
= 0.067 * 0.1
= 0.0067
no. of moles of solute = given mass / molar mass
0.0067 = 0.138 / molar mass
molar mass = 0.138 / 0.0067
molar mass of an acid = 20.59 g