Question

In: Chemistry

A 236.4 mL sample of water contains 0.0294 g of NaCl. Calculate the concentration in ppm....

A 236.4 mL sample of water contains 0.0294 g of NaCl. Calculate the concentration in ppm.

concentration = ___ ppm

Solutions

Expert Solution

Ans. ppm = parts per million. 1 million = 106

1 ppm means 1 part of solute in 106 parts of the solution.

Assuming, 1gram = 1 ml           [i.e. density of water]

1 gram in 106 mL is 1 ppm.

or, 106 mL = 103 L ; so, 1 gram in 1000 L is also 1 ppm.

Also, 1 gram = 1000 mg

Now, 1000mg in 1000L is 1 ppm. Or, 1 mg in 1L is 1 ppm.

It can be expressed in so many ways.

Given, 236.4 mL water has 0.0294 g NaCl.

Amount of NaCl in 1000 mL (= 1L) = (0.0294 / 236.4) x 1000 = 0.1243654822335025 gra                                                                                                       = 124.36 mg

That is, concentration of NaCl = 124.36 mg in 1 L

Thus, it’s 124.36 ppm.


Related Solutions

A) Calculate the concentration in ppm and the molarity of Cd in a 2.00 mL sample...
A) Calculate the concentration in ppm and the molarity of Cd in a 2.00 mL sample which has been shown to contain 16.4 μg Cd. Assume the sample has a density of 1.00 g/mL.
Calculate the concentration in ppm and the molarity of Cd in a 2.00 mL sample which...
Calculate the concentration in ppm and the molarity of Cd in a 2.00 mL sample which has been shown to contain 16.4 μg Cd. Assume the sample has a density of 1.00 g/mL.
A sample of water with a Fe2+ concentration of 500 ppm. Additionally Eh is 0.503 V...
A sample of water with a Fe2+ concentration of 500 ppm. Additionally Eh is 0.503 V and pH is 3.45. Will Fe(OH)3(s) stay in solution? What would be the equilibrium Eh at this pH?
Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the...
Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the following data were obtained. Titrant is 0.0505 M EDTA, 13.49 mL were used when an aliquot of the sample was at pH 13.0, 16.99 mL were used for an aliquot at pH 10.5.
Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the...
Determine the calcium content (in ppm) of a 100.00 mL sample of drinking water if the following data were obtained. Titrant is 0.0421 M EDTA, 13.84 mL were used when an aliquot of the sample was at pH 13.0, 19.36 mL were used for an aliquot at pH 10.5.
A 0.9140 g sample of a mixture of NaCl and KCl is dissolved in water, and...
A 0.9140 g sample of a mixture of NaCl and KCl is dissolved in water, and the solution is then treated with an excess of AgNO3 to yield 1.943 g of AgCl. Calculate the percent by mass of each compound in the mixture.
A 0.9000 g sample of a mixture of NaCl and KCl is dissolved in water, and...
A 0.9000 g sample of a mixture of NaCl and KCl is dissolved in water, and the solution is then treated with an excess of AgNO3 to yield 1.923 g of AgCl. Calculate the percent by mass of each compound in the mixture. ____% mass of NaCl ____% mass of KCl
The concentration of an undiluted sample is 26.4 mg/ml. To calculate that answer, the concentration of...
The concentration of an undiluted sample is 26.4 mg/ml. To calculate that answer, the concentration of the diluted sample was multiplied by the dilution factor. Knowing that the dilution factor is 2, work backwards to determine the concentration of the DILUTED sample. A. 13.2 mg/ml B. 132.0 mg/ml C. 1.32 mg/ml D. 26.4 mg/ml What is the unit used to describe cell solutions measured in a spectrophotometer? Cells/milliliter Grams (g) Optical density (OD) Meters (m) Spectroscopy is based on the...
Calculate the concentration in osmolarity of a solution prepared by adding 5.00 g NaCl (molar mass...
Calculate the concentration in osmolarity of a solution prepared by adding 5.00 g NaCl (molar mass = 58.44) to a 100 mL volumetric flask, filling the flask to the mark with distilled water, and mixing.
Calculate the final concentration (in Molarity) when 25 mL of water is added to 95 mL...
Calculate the final concentration (in Molarity) when 25 mL of water is added to 95 mL of 1.7 M LiCl. Show your work. Part E - How many grams of KCl must be added to depress the freezing point of 1.00 kg of water to a temperature of -2.0 C? Show your work. Part F - What is the maximum number of grams of KI that can be added to 40. g of water before any precipitation is formed at...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT