series from n=1 to infinity of (4n) / [ (3n^3/2) +7n -9]. the answer should include...

series from n=1 to infinity of (4n) / [ (3n^3/2) +7n -9]. the answer should include if its converging or diverging by which method

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milcah answered 2 years ago

Determine if ∑(-1)^n/(4n-7), n=0 to infinity, absolutely or conditionally converges or diverges?

1- Show that (n^3+3n^2+3n+1) / (n+1) is O (n2 ). Use the definition and proof of...

1- Show that (n^3+3n^2+3n+1) / (n+1) is O (n2 ). Use the definition and proof of big-O notation. 2- Prove using the definition of Omega notation that either 8 n is Ω (5 n ) or not. please help be with both

a) Prove that n 3 − 91n 2 − 7n − 14 = Ω(n 3 )....

a) Prove that n 3 − 91n 2 − 7n − 14 = Ω(n 3 ). Your answer must clearly specify the constants c and n0. b) Let g(n) = 27n 2 + 18n and let f(n) = 0.5n 2 − 100. Find positive constants n0, c1 and c2 such that c1f(n) ≤ g(n) ≤ c2f(n) for all n ≥ n0. Be sure to explain how you arrived at the constants.

Derive the Sackur-Tetrode equation starting from the multiplicity givenin Ch. 2: Ω =(1/N!)(V^{N}/h^{3N})(pi^{3N/2}/3N^{2}!)(2mU)^{3N/2} The Sackur-Tetrode equation...

Derive the Sackur-Tetrode equation starting from the multiplicity givenin Ch. 2: Ω =(1/N!)(V^{N}/h^{3N})(pi^{3N/2}/3N^{2}!)(2mU)^{3N/2} The Sackur-Tetrode equation is: S=Nk[ln((V/N)((4pi*m*U)/(3Nh^{2}))^{3/2})+(5/2)]

convergent or divergent infinity sigma n = 1 sqrt(n^5+ n^3 -7) / (n^3-n^2+n)

1. Prove or Disprove: If n is a nonnegative integer, then 5 | (24n + 39n)

1. Prove or Disprove: If n is a nonnegative integer, then 5 | (2*4n + 3*9n)

1. Test the series below for convergence using the Root Test. ∞∑n=1 (2n/7n+5)^n The limit of...

1. Test the series below for convergence using the Root Test. ∞∑n=1 (2n/7n+5)^n The limit of the root test simplifies to lim n→∞ |f(n)| where f(n)= The limit is: Based on this, the series Diverges Converges 2. Multiple choice question. We want to use the Alternating Series Test to determine if the series: ∞∑k=4 (−1)^k+2 k^2/√k5+3 converges or diverges. We can conclude that: The Alternating Series Test does not apply because the terms of the series do not alternate. The...

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series from n=1 to infinity of (4n) / [ (3n^3/2) +7n -9]. the answer should include...

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