Question

In: Statistics and Probability

A 99% confidence interval for a population mean was reported to be 154 to 158. If...

A 99% confidence interval for a population mean was reported to be 154 to 158. If 15, what sample size was used in this study? (Round your answer to next whole number.)

Solutions

Expert Solution

Solution:

A 99% confidence interval for a population mean was reported to be 154 to 158.

Lower limit = 154

Upper limit = 158

Margin of error = (Upper - Lower)2 = (158 -154)/2

E = 2

Given that population SD is 15

= 15

For 99% confidence ,

c = 0.99

= 1- c = 1- 0.99 = 0.01

  /2 = 0.01 2 = 0.005 and 1- /2 = 0.995

Search the probability 0.995 in the Z table and see corresponding z value

= 2.576   

Now, sample size (n) is given by,

= {(2.576 * 15)/ 2 }2

=  374

Answer : 374

=     ..(round to the next whole number)


Related Solutions

Assuming that the population is normally​ distributed, construct a 99% confidence interval for the population​ mean,...
Assuming that the population is normally​ distributed, construct a 99% confidence interval for the population​ mean, based on the following sample size of n=7.​ 1, 2,​ 3,4, 5, 6​,and 30   Change the number 30 to 7 and recalculate the confidence interval. Using these​ results, describe the effect of an outlier​ (that is, an extreme​ value) on the confidence interval. Find a 99 % confidence interval for the population mean. ​(Round to two decimal places as​ needed.) Change the number 30...
assuming that the population is normally distributed, construct a 99% confidence interval for the population mean,...
assuming that the population is normally distributed, construct a 99% confidence interval for the population mean, based on the following sample size n=6. 1,2,3,4,5 and 29. in the given data, replace the value 29 with 6 and racalculate the confidence interval. using these results, describe the effect of an outlier on the condidence interval, in general find a 99% confidence interval for the population mean, using the formula.
Assuming that the population is normally​ distributed, construct a 99​% confidence interval for the population mean...
Assuming that the population is normally​ distributed, construct a 99​% confidence interval for the population mean for each of the samples below. Explain why these two samples produce different confidence intervals even though they have the same mean and range. Sample​ A: 1   4   4   4   5   5   5   8 Sample B: 1   2   3   4   5   6   7   8 Construct a 99​% confidence interval for the population mean for sample A. less than or equalsmuless than or equals Type...
Assuming that the population is normally​ distributed, construct a 99% confidence interval for the population mean...
Assuming that the population is normally​ distributed, construct a 99% confidence interval for the population mean for each of the samples below. Explain why these two samples produce different confidence intervals even though they have the same mean and range. SAMPLE A: 1 1 4 4 5 5 8 8 SAMPLE B: 1 2 3 4 5 6 7 8 1.Construct a 99% confidence interval for the population mean for sample A. ( type integers or decimals rounded to two...
Determine the margin of error for a 99​% confidence interval to estimate the population mean when...
Determine the margin of error for a 99​% confidence interval to estimate the population mean when s​ = 43 for the sample sizes below. ​a) n=12 ​b) n=25 ​c) n=46 ​a) The margin of error for a 99​% confidence interval when n=12 is _.
Determine the margin of error for a 99% confidence interval to estimate the population mean when...
Determine the margin of error for a 99% confidence interval to estimate the population mean when s=45 for the sample sizes of n=15, n=34, n=54. (Find the margin of error for each interval when n=x) Determine the margin of error for a confidence interval to estimate the population mean with n=24 and s=12.3 for confidence levels 80%, 90%, 99%.
Microsoft MiniTab Assignment Construct and interpret the 99 % confidence interval estimate of the population mean...
Microsoft MiniTab Assignment Construct and interpret the 99 % confidence interval estimate of the population mean “WaitTime” for all customers. Type in your explanation below the output from Minitab. Construct and interpret the 99% confidence interval estimate of the population proportion of male customers. Type in your explanation below the output from Minitab. Is the mean “Income” for all customers no more than $38,000? Perform the appropriate hypothesis test using alpha = 0.05. Type in your explanation below the output...
Construct a 99% confidence interval estimate of the population mean. Is the result dramatically different from the 99% confidence interval found in Exercise 18 in Section 7-2?
Speed Dating Use these female measures of male attractiveness given in Exercise 18 “Speed Dating” in Section 7-2 on page 329: 5, 8, 3, 8, 6, 10, 3, 7, 9, 8, 5, 5, 6, 8, 8, 7, 3, 5, 5, 6, 8, 7, 8, 8, 8, 7. Use the bootstrap method with 1000 bootstrap samples. Construct a 99% confidence interval estimate of the population mean. Is the result dramatically different from the 99% confidence interval found in Exercise 18 in...
Construct a 99% confidence interval on the population variance and the population standard deviation for the...
Construct a 99% confidence interval on the population variance and the population standard deviation for the data listed below: 91.8, 112.1, 138.3, 90.6, 136.6, 113.6, 101.5, 123.6, 81.4, 119.2, 111.4, 89.4, 110.5, 80.5, 94.8, 117.0, 105.7, 146.6, 138.6, 99.9, 106.6
Construct a 99​% confidence interval to estimate the population mean using the data below. X (overbar)...
Construct a 99​% confidence interval to estimate the population mean using the data below. X (overbar) = 22 s = 3.2 n = 13 What assumptions need to be made about this​ population? The 99​% confidence interval for the population mean is from a lower limit of __ to an upper limit of __. (round to two decimal places as needed.)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT