Question

In: Statistics and Probability

For a standard normal distribution, find 1. P(z > c)=0.3796 Find c. 2. P(z < c)=0.0257...

For a standard normal distribution, find

1. P(z > c)=0.3796
Find c.

2. P(z < c)=0.0257
Find c.

3. P(-2.68< z > -0.38)

4. P(z > -1.55)

5. P(z < -0.32)

Solutions

Expert Solution

solution

1)Using standard normal table,

P(Z > c) = 0.3796

= 1 - P(Z < c) = 0.3796

= P(Z < c ) = 1 - 0.3796

= P(Z < c ) = 0.6204

= P(Z < 0.31 ) = 0.6204  

c=0.31 (using standard normal (Z) table )

(2)

Using standard normal table,

P(Z < c) = 0.0257

= P(Z < c) =0.0257

= P(Z < -1.95 ) = 0.0257

c = - 1.95 Using standard normal z table,

(3)P(-2.68< z > -0.38)

= P(Z <-0.38 ) - P(Z < -2.68)

Using z table,  

= 0.3520-0.0037

probability=0.3483

(4)

P(z >-1.55 ) =1 - P(z <-1.55 )

Using z table,
= 1 -0.0606

= 0.9394

probability=0.9394

(5) P(z <-0.32 )

Using z table  

=0.3745

probability=0.3745


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