1.
a) For a standard normal distribution, find c if P(z < c) =
0.4756 c =
b) For a standard normal distribution, find c if P(z > c) =
0.2399 For greatest accuracy, don't use Z tables. c =
Let z be a random variable with a standard normal
distribution.
Find “a” such that P(|Z| <A)= 0.95
This is what I have:
P(-A<Z<A) = 0.95
-A = -1.96
How do I use the symmetric property of normal distribution to make
A = 1.96?
My answer at the moment is P(|z|< (-1.96) = 0.95