For a standard normal distribution, find: P(z > c) = 0.9228 Find c rounded to two...

For a standard normal distribution, find: P(z > c) = 0.9228 Find c rounded to two decimal places.

Expert Solution

Solution:

Given: P(z > c) = 0.9228

We have to find c value.

If P(z > c) = 0.9228 then

P( z < c )= 1 - P(z > c)

P( z < c )= 1 - 0.9228

P( z < c )= 0.0772

Look in z table for Area = 0.0772 or its closest area and find corresponding z value.

Area 0.0778 is closest to 0.0772 and it corresponds to -1.4 and 0.02

thus z = -1.42

that is: c = -1.42

Thus required value of c = -1.42

orchestra answered 2 years ago

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