In: Chemistry
Consider the bromination of 1-pentanol by HBr to form 1-bromopentane.
CH3(CH2)3CH2OH + HBr ---> CH3(CH2)3CH2Br + H2O
1 pentanol mol. weight 88 g/mol
hydrobromic acid 80.9 g/mol
1-bromopentane 151 g/mol
nitric acid 63 g/mol
a) If you had 44 g of 1-pentanol, 34 g of HBr and 1.7 g of nitric acid, what would be the limiting reagent in this reaction?
b) What is the theoretical yield of 1-bromopentane in (a) ?
c) If you obtained 16.0 g of 1-bromopentane, what is the % yield for the reaction?