Question

Name the compound: (CH3)3N_______

What is the name of CH₃(CH₂)₆COOH? ______________

The reaction of a carboxylic acid with an alcohol in the presence of strong acid produces________________

What are the products of the reaction of pentanoic acid with the strong base potassium hydroxide? _____________

Answer 1

Answer 1) Common and IUPAC names of amine are given in image file. In IUPAC nomenclature name of compound ends with -amine. Substituent of N are with N prefix and repeated for more than one substituted.

Answer 2) IUPAC name of carboxylic acid is given in image file. Name of carboxylic acid ends with -oic acid.

Answer 3)

i) Carboxylic acid on reaction with an alcohol in presence of strong acid undergo esterification reaction. This is reversible reaction.

ii) OH of carboxyl group gets protonated preferentially in acidic medium. Then alcohol attacks carbonyl C of acid. The reversal of –ve charge on carbonyl O knock outs H2O –a neutral molecule.

iii) Then loss of proton generates an ester.

iv) Reaction is reversible as ester generated is more reactive towards nucleophilic attack. A solution still contains H2O which serves as nucleophile and reverses reaction to starting compound acid.

Answer 4) Carboxylic acids on treatment of strong base KOH evolves H2 gas and forms corresponding salt I.e. Potassium salt of acid.

In pentanioc acid case it will forms potassium sale of pentanioc acid.