In: Chemistry
hybridization of H2C=CH-CH2-CH3
H2Ca=CbH-CcH2-CdH3
carbon a and b are sp2 hybridized (double bonded)
carbon c and d are sp3 hybridized
explanation:
Carbon has electron configuration 1s2 2s2 2px1 2py1 2pz0 with its 6 electrons.The valence orbitals undergo hybridization to form orbitals of equal energy.
For a carbon,with all single bonds ,one s and three p orbitals form sp3 hybridized orbitals .In the above molecule ,carbon c and d forms four single bonds with these hybrid orbitals as follows:
For the carbon a and b, one s and two p orbitals form sp2 hybridized orbitals,while one p remains to form a pi bond with the left over p in the neighboring carbon(also sp2).Thus, carbon a and b are bonded to each other by a sigma bond ( one of the sp2 orbitals on each carbons bond to each other) as well as by a pi bond.They are doubly bonded to each other.