Question

Please find the mean, mode, medium as applicable. This is data collected based off an observational study I conducted. The data was collected to see if male or females actively or passively interacted with the the barista while placing their order. This first table is the study of both locations compressed in to one table. The second table is data that is specific to the location. Please include/ find P value and stats!

Gender	Observed	Active	Passive
Male	26	18	8
Female	21	15	6
Total	47	33	14
Location	Observed	Active	Passive
Panera (PM)	27	21	6
Dunkin (AM)	20	10	10
Total	47	21	16

Answer 1

Please find the mean, mode, medium as applicable. This is data collected based off an observational study I conducted. The data was collected to see if male or females actively or passively interacted with the the barista while placing their order. This first table is the study of both locations compressed in to one table. The second table is data that is specific to the location. Please include/ find P value and stats!

Gender	Observed	Active	Passive
Male	26	18	8
Female	21	15	6
Total	47	33	14
Location	Observed	Active	Passive
Panera (PM)	27	21	6
Dunkin (AM)	20	10	10
Total	47	21	16

First table:

Chi-Square Test
Observed Frequencies
	Column variable					Calculations
Row variable	Observed	Active	Passive	Total		fo-fe
Male	26	18	8	52		0.0000	-0.2553	0.2553
Female	21	15	6	42		0.0000	0.2553	-0.2553
Total	47	33	14	94
Expected Frequencies
	Column variable
Row variable	Observed	Active	Passive	Total		(fo-fe)^2/fe
Male	26	18.2553	7.7447	52		0.0000	0.0036	0.0084
Female	21	14.7447	6.2553	42		0.0000	0.0044	0.0104
Total	47	33	14	94
Data
Level of Significance	0.05
Number of Rows	2
Number of Columns	3
Degrees of Freedom	2
Results
Critical Value	5.9915
Chi-Square Test Statistic	0.0268
p-Value	0.9867
Do not reject the null hypothesis

Calculated chi square =0.0268

DF=2

Chi square value at 0.05 level =5.991

Calculated chi square =0.0268 < 5.991 the table value.

The null hypothesis is not rejected.

P value= 0.9867

There is no association between gender and actively or passively interacted with the barista while placing order.

Second table:

Chi-Square Test
Observed Frequencies
	Column variable					Calculations
Row variable	Observed	Active	Passive	Total		fo-fe
Panera (PM)	27	21	6	54		0.0000	3.1915	-3.1915
Dunkin (AM)	20	10	10	40		0.0000	-3.1915	3.1915
Total	47	31	16	94
Expected Frequencies
	Column variable
Row variable	Observed	Active	Passive	Total		(fo-fe)^2/fe
Panera (PM)	27	17.8085	9.1915	54		0.0000	0.5720	1.1082
Dunkin (AM)	20	13.1915	6.8085	40		0.0000	0.7721	1.4960
Total	47	31	16	94
Data
Level of Significance	0.05
Number of Rows	2
Number of Columns	3
Degrees of Freedom	2
Results
Critical Value	5.9915
Chi-Square Test Statistic	3.9483
p-Value	0.1389
Do not reject the null hypothesis

Calculated chi square =3.948

DF=2

Chi square value at 0.05 level =5.991

Calculated chi square =3.948 < 5.991 the table value.

The null hypothesis is not rejected.

P value= 0.1389

There is no association between location and actively or passively interacted with the barista while placing order.