In: Statistics and Probability
Use the following information for the next four problems. A researcher is interested in estimating the mean salary of public school teachers in a particular region. A random sample of 9 teachers is selected and the salary of each one is recorded. The researcher calculates a sample mean of $45,000 and a sample standard deviation of $1,600. Assume that the salaries in the population vary according to a normal distribution.
The mean salary of all public school teachers in the region is a __________ while the sample mean $45,000 is a __________.
| a. | 
 parameter, statistic  | 
|
| b. | 
 statistic, parameter  | 
|
| c. | 
 parameter, parameter  | 
|
| d. | 
 statistic, statistic  | 
Calculate a 95% confidence interval to estimate the mean salary.
| a. | 
 $45,000 $348.44  | 
|
| b. | 
 $45,000 $1,206.40  | 
|
| c. | 
 $45,000 $1,229.87  | 
|
| d. | 
 $45,000 $1,045.33  | 
Suppose, instead, that a larger sample of teachers had been selected while still using the 95% confidence level. The new confidence interval, based on the larger sample, would be __________ the interval in the previous problem.
| a. | 
 shorter than  | 
|
| b. | 
 the same length as  | 
|
| c. | 
 longer than  | 
1 )The mean salary of all public school teachers in the region is a parameter while the sample mean $45,000 is a statistic.
option A is true
2 ) using excel we have
| Confidence Interval Estimate for the Mean | |
| Data | |
| Sample Standard Deviation | 1600 | 
| Sample Mean | 45000 | 
| Sample Size | 9 | 
| Confidence Level | 95% | 
| Intermediate Calculations | |
| Standard Error of the Mean | 533.3333333 | 
| Degrees of Freedom | 8 | 
| t Value | 2.306004135 | 
| Interval Half Width | 1229.868872 | 
| Confidence Interval | |
| Interval Lower Limit | 43770.13 | 
| Interval Upper Limit | 46229.87 | 
\ a 95% confidence interval to estimate the mean salary is given by option c
option a is true 3 )Suppose, instead, that a larger sample of
teachers had been selected while still using the 95% confidence
level. The new confidence interval, based on the larger sample,
would be shorter than the interval in the previous
problem.