In: Statistics and Probability
Use the following information for the next four problems. Suppose that a researcher is interested in estimating , the proportion of all people in a particular area with diabetes.
Suppose the researcher selects a random sample of 500 people and finds 47 of them to have diabetes. Calculate a 95% confidence interval to estimate the proportion of all people in the area with diabetes.
| a. | 
 0.094 0.021  | 
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| b. | 
 0.094 0.083  | 
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| c. | 
 0.094 0.026  | 
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| d. | 
 0.094 0.012  | 
Refer back to the story and to the confidence interval in Problem 6. Select the pair of words below that best completes the following two statements.
(i) A 99% confident interval (based on the original sample of 500 people) would be __________ than the confidence interval in Problem 6.
(ii) A 95% confident interval based on a larger sample (assuming that the value of doesn’t change) would be __________ than the confidence interval in Problem 6.
| a. | 
 (i) longer (ii) longer  | 
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| b. | 
 (i) longer (ii) shorter  | 
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| c. | 
 (i) shorter (ii) shorter  | 
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| d. | 
 (i) shorter (ii) longer  | 
For the next two problems only, suppose that the confidence interval in Problem 6 had ranged from 0.074 to 0.114.
Which one of the following would give a correct interpretation?
| a. | 
 We are 95% confident that , the population percent, is between 0.074 and 0.114.  | 
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| b. | 
 We are confident that 95% of the people in the area have diabetes.  | 
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| c. | 
 We are 95% confident that , the sample percent, is between 0.074 and 0.114.  | 
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| d. | 
 We are 95% confident that exactly 47 people have diabetes.  | 
Suppose someone makes the claim that 8% of the people in the area have diabetes. Should we believe the claim? Why or why not?
| a. | 
 We should believe the claim because 8% is in the confidence interval.  | 
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| b. | 
 We should believe the claim because 8% is not in the confidence interval.  | 
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| c. | 
 We should not believe the claim because 8% is in the confidence interval.  | 
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| d. | 
 We should not believe the claim because 8% is not in the confidence interval.  | 
Drivers in the United States are keeping their cars longer. To plan production and sales events, a company wants to estimate the proportion of automobiles that are more than ten years old and still on the road. The company wants to be 95% confident that their sample estimate is accurate to within 4% of the actual population proportion. How large of a sample should the company select? (Assume that there is no prior information regarding the true value of the population proportion. Hint – that means to let = 0.50.)
| a. | 
 4  | 
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| b. | 
 142  | 
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| c. | 
 13  | 
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| d. | 
 601  | 
1)
| sample success x = | 47 | |
| sample size n= | 500 | |
| sample proportion p̂ =x/n= | 0.0940 | |
| std error se= √(p*(1-p)/n) = | 0.0131 | |
| for 95 % CI value of z= | 1.960 | |
| margin of error E=z*std error = | 0.0256 | |
option C is correct : 0.094 -/+ 0.026
2)option B is correct
(i) longer (ii) shorter
3)
option A
We are 95% confident that , the population percent, is between 0.074 and 0.114.
4)
option A
We should believe the claim because 8% is in the confidence interval.
5)
| here margin of error E = | 0.04 | |
| for95% CI crtiical Z = | 1.960 | |
| estimated prop.=p= | 0.5000 | |
| reqd. sample size n= | p*(1-p)*(z/E)2= | 601 |