In: Statistics and Probability
Use the following information for the next three problems. Suppose that = 30% of the students at a large university must take a statistics course. Suppose that a random sample of 50 students is selected. Let = the percent of students in the sample who must take statistics.
Different samples will produce different values of . In order for the values of to vary according to a normal model, we need to check two conditions. Which two of the following need to be checked?
a. |
The sample size is large (). |
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b. |
The sample observations are independent of each other. |
|
c. |
and |
|
d. |
The population distribution is normal in shape. |
QUESTION 4
95% of all samples will produce a between __________ and __________.
a. |
0.235 and 0.365 |
|
b. |
0.280 and 0.320 |
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c. |
0.105 and 0.495 |
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d. |
0.170 and 0.430 |
QUESTION 5
What is the chance that more than 38% of the students in a sample must take statistics (i.e. what is the chance that > 0.38)?
a. |
0.6480 |
|
b. |
0.8907 |
|
c. |
0.1093 |
|
d. |
1.23 |
b.
The sample observations are independent of each other.
d.
The population distribution is normal in shape.
4)
Sample proportion (\hat{p}) = 0.30
Sample size (n) = 50
Confidence interval(in %) = 95
z @ 95% = 1.96
Since we know that
Required confidence interval = (0.3-0.127, 0.3+0.127)
Required confidence interval = (0.173, 0.427)
Option d 0.170 and 0.430
5)
Mean =0.35
S.d. =
P(x > 0.38)=?
The z-score at x = 0.38 is,
z = 0.38-0.3\0.0648
z = 1.2346
This implies that
P(x > 0.38) = P(z > 1.2346) = 1 - 0.8915102954927918
P(x > 0.38) = 0.1085
Option C