Question

In: Biology

At what substrate concentration would an enzyme with Km of 5mM operate at one-quarter its maximum...

At what substrate concentration would an enzyme with Km of 5mM operate at one-quarter its maximum rate? Give your answer in units of mM to 1 decimal place.

Expert Solution

Michaelis–Menten equation for Enzyme is

V0 = Vmax[S] / Km +[S]

V0 = Initial reaction rate

Vmax = the maximum reaction rate,

[S] = the initial substrate concentration

Km = Michaelis constant

According to the question,

V0 = ¼ th Vmax

Km = 5 mM

Putting these values in the equation, we got,

¼ Vmax = Vmax[S] / 5 mM +[S]

or ¼ = [S] / 5 mM +[S] (cancelling Vmax from both the sites)

or 5 mM +[S] = 4[S]

or 5 mM = 3 [S]

or [S] = 5/3 mM = 1.66 mM = 1.7 mM (approx)

At 1.7 mM substrate concentration an enzyme with Km of 5mM would operate at one-quarter its maximum rate.

Kindly revert for any query and concern

gladiator answered 1 month ago

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