In: Statistics and Probability
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 433 gram setting. It is believed that the machine is underfilling the bags. A 42 bag sample had a mean of 425 grams. Assume the population variance is known to be 625. A level of significance of 0.05 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Solution :
= 433
=425
2 = 625
=25
n = 42
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 433
Ha : 433
Test statistic = z
= ( - ) / / n
= (425 -433) / 25 / 42
= −2.074
Test statistic = z = −2.07
P-value = 0.0381
= 0.05
P-value <
0.0381 < 0.05
Reject the null hypothesis .
There is sufficient evidence to suggest that