In: Statistics and Probability
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is believed that the machine is underfilling the bags. A 49 bag sample had a mean of 413 grams. Assume the population variance is known to be 676. A level of significance of 0.1 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Solution,
The null and alternative hypothesis is ,
H0 :  
= 420
Ha : 
 < 420
= 413
2 = 676
 = 
2 = 
676 =
26
n = 49
Test statistic = z =
= (
- 
 ) / 
 / 
 n
= (413 - 420) / 26 / 
49
Test statistic = z = -1.88
This is the left tailed test .
P (Z < -1.88)
P-value = 0.0301
= 0.1
P-value < 
Reject the null hypothes