In: Statistics and Probability
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 440 gram setting. It is believed that the machine is underfilling the bags. A 21 bag sample had a mean of 430 grams with a standard deviation of 29 . Assume the population is normally distributed. A level of significance of 0.02 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places
Null hypothesis
Alternative hypothesis
We have for given sample,
Population mean for given sample=440
Sample mean=430
Sample standard deviation s=29
Sample size =n= 21
Degree of freedom = n-1 =20
t test statistic formula is
P value is 0.0649......................by using Excel command TDIST(-1.58,20,1)
0.05< P value < 0.10
P value is 0.0649>0.02
Therefore, we fail to reject H0 at level of significance of 0.02 .
Conclusion: We do not have sufficient evidence at level of significance of 0.02 to say that ,the machine is underfilling the bags.