Question

In: Chemistry

1. Combining 0.371 mol Fe2O30.371 mol Fe2O3 with excess carbon produced 18.9 g Fe.18.9 g Fe....

1.

Combining 0.371 mol Fe2O30.371 mol Fe2O3 with excess carbon produced 18.9 g Fe.18.9 g Fe.

Fe2O3+3C⟶2Fe+3COFe2O3+3C⟶2Fe+3CO

What is the actual yield of iron in moles?

actual yield:

molmol

What is the theoretical yield of iron in moles?

theoretical yield:

molmol

What is the percent yield?

percent yield:

%

Expert Solution

Fe2O3+3C⟶2Fe+3CO

1 mole of Fe2O3 react with excess of C to gives 2 moles of Fe

0.371 moles of Fe2O3 react with excess of C to gives = 2*0.371/1 = 0.742 moles of Fe

Theoretical yield of iron = 0.742moles

no of moles of iron = W/G.A.Wt

= 18.9/55.845 = 0.3384moles

Actual yield of iron = 0.3384moles

percent yield = Actual yield*100/Theoretical yield

= 0.3384*100/0.742 = 45.6% >>>>.answer

queen_honey_blossom answered 2 years ago

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