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the reaction of 7.26 g of carbon with excess O2 yeilds 8.20 g of CO2. What...

the reaction of 7.26 g of carbon with excess O2 yeilds 8.20 g of CO2. What is the percent yeild of the reaction?

Solutions

Expert Solution

  C           +         O2      ----------->          CO2

1 mol                                                     1 mol

= 12 g                                                     = 44 g

In the above balanced equation,

          12g of carbon with excess O2 produced   44g of CO2

So, 7.26 g of carbon with excess O2 will produce ? g of CO2.

         ? = (7.26 g of carbon/12 g of carbon) x 44g of CO2

            = 26.62 g   CO2

7.26 g of carbon with excess O2 will produce 26.62 g of CO2. (This is called theoretical yield)

But it is given that 7.26 g of carbon with excess O2 yeilds 8.20 g of CO2. (This is called actual yield)

Percent yield = (actual yield / theoretical yield) x 100

                       = (8.20 g CO2 / 26.62 g CO2) X 100

                      = 30.80 %

Percent yield = 30.80 %

Therefore, percent yield of the reaction = 30.80 %

queen_honey_blossom answered 3 days ago
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