In: Statistics and Probability
A school counselor has been working with a group of six-graders with special needs. She hypothesized that students like her group may have higher depression scores compared to the national average for six-graders. So she assessed her group of students with a depression scale for children and compared the scores to the national average through a t test. The t statistic turned out to be .20. Using a significance level of .01, what decision should she make regarding the null hypothesis?
A.Postpone any decisions until a more conclusive study could be conducted
B.There is not enough information given to make a decision
C.Reject it
D.Fail to reject it
Solution:
Given the information about the t test for the population mean.
Claim by a school counselor is " students like her group may have higher depression scores compared to the national average for six-graders".
See the word "higher".
So, the claim is " is higher than the national average "
i.e our alternative hypothesis is H1: >
> sign indicates that the test is "right tailed test"
The critical value is and the critical region is > .
Now,
t = 0.20 ...the value of test statistic
= 0.01 .. significance level.
But, the sample size n is not given. So,we cant find .
So answer is
B.There is not enough information given to make a decision