Question

In: Statistics and Probability

A manufacturer claims that the average mileage of his automobiles is at least 25mpg. In a...

A manufacturer claims that the average mileage of his automobiles is at least 25mpg. In a previous study it was found that the standard deviation of the mileage of his automobiles is 3mpg. For a .05 level of significance, what sample size would be recommended if the researcher wants an 80% chance of detecting that is less than 25 miles per gallon when it is actually 24 (to the next whole number)?

A. 71

B. 95

C. 56

D. 28

Solutions

Expert Solution

Hypothesized mean                =μ o        = 25
true mean                                    =μa                                         = 24
standard deviation                  =σ   = 3
for 0.05 level and right tailed test critival value Zα = 1.6449
for 0.2 level of type II error critival value Zβ = 0.8416
required sample size             =n =(Zα+Zβ)2σ2/(μoa)2
= 56.00

option C is corect


Related Solutions

A sprinkler manufacturer claims that the average activating temperatures is at least 132 degrees. To test...
A sprinkler manufacturer claims that the average activating temperatures is at least 132 degrees. To test this claim, you randomly select a sample of 32 systems and find the mean activation temperature to be 133 degrees. Assume the population standard deviation is 3.3 degrees. Find the standardized test statistic and the corresponding p-value. z-test statistic = -1.71, p-value = 0.0432 z-test statistic = 1.71, p-value = 0.0432 z-test statistic = 1.71, p-value = 0.0865 z-test statistic = -1.71, p-value =...
A sprinkler manufacturer claims that the average activating temperatures is at least 132 degrees. To test...
A sprinkler manufacturer claims that the average activating temperatures is at least 132 degrees. To test this claim, you randomly select a sample of 32 systems and find the mean activation temperature to be 133 degrees. Assume the population standard deviation is 3.3 degrees. Find the standardized test statistic and the corresponding p-value. z-test statistic = -1.71, p-value = 0.0432 z-test statistic = 1.71, p-value = 0.0432 z-test statistic = 1.71, p-value = 0.0865 z-test statistic = -1.71, p-value =...
HW #44. 5 The manufacturer of a particular brand of tires claims they average at least...
HW #44. 5 The manufacturer of a particular brand of tires claims they average at least 50,000 miles before needing to be replaced. From past studies of this tire, it is known that the population standard deviation is 8,000 miles. A survey of tire owners was conducted. From the 23 tires surveyed, the mean lifespan was 45500 miles. Using alpha = 0.05, can we prove that the data in inconsistent with the manufacturers claim? We should use a ? t...
The manufacturer of an Engine Energizer System (EES) claims that it improves gas mileage and reduces...
The manufacturer of an Engine Energizer System (EES) claims that it improves gas mileage and reduces emissions in automobiles by using magnetic-free energy to increase the amount of oxygen in the fuel for greater combustion efficiency. Following are test results, performed under international and U.S. government agency standards, on a random sample of 14 vehicles. The data (also see file M09_Gas_Paired.txt) give the carbon monoxide (CO) levels, in parts per million, of each vehicle tested, both before installation of EES...
A consumer agency claims that the average fuel mileage of Sedan A exceeds that of Sedan...
A consumer agency claims that the average fuel mileage of Sedan A exceeds that of Sedan B. To test this claim, a random sample of 17 Sedan A vehicles were tested and the sample mean fuel mileage was found to be 28.25 miles per gallon with a known population standard deviation of 1.30 miles per gallon. A random sample of 14 Sedan B vehicles also were tested and the sample mean fuel mileage was found to be 27.25 miles per...
An auto maker claims that the mean gas mileage of its luxury sedan is at least...
An auto maker claims that the mean gas mileage of its luxury sedan is at least 25 miles per gallon. A random sample of 36 such cars were tested and resulted in a sample mean of 24.2 miles per gallon and a sample standard deviation of 2.8 miles per gallon. At α = 0.05, is there sufficient evidence to reject the auto maker’s claim? Claim: H0: H1: Test Statistic: Critical Region/Critical Value: Decision about H0:
According to Energy Information the average gas mileage of all automobiles is 21.4 miles per gallon....
According to Energy Information the average gas mileage of all automobiles is 21.4 miles per gallon. For a random sample of 40 sport utility vehicles, the mean gas mileage is 19.8 miles per gallon with a standard deviation of 3.5 miles per gallon. Test the claim that the mean mileage of all SUVs is different than the gas mileage of all automobiles. a) z = 2.89 and a p value of .9938 .9938 < 0.05 There is not sufficient evidence...
The EPA sticker for a particular model of automobile claims the car has average highway mileage...
The EPA sticker for a particular model of automobile claims the car has average highway mileage of 35 miles per gallon. A consumer advocacy group takes a random sample of 30 of these cars and finds that they have an average mileage of 33.6 miles per gallon with a standard deviation of 3 miles per gallon. Do the results of this test provide sufficient evidence to conclude that the actual mileage of this model is less than 35 miles per...
A manufacturer claims that the average tread life of a premium tire exceeds the average tread...
A manufacturer claims that the average tread life of a premium tire exceeds the average tread life of economy tire of the same size by at least 5000 miles. To test this claim, 50 pieces of each type of tires were tested under similar conditions. The premium tire had an average tread life of 43000 miles with a sample standard deviation of 2300, while economy tire had an average tread life of 37500 miles with a sample standard deviation of...
A manufacturer of light bulbs claims that the average lifetime of one of their bulbs is...
A manufacturer of light bulbs claims that the average lifetime of one of their bulbs is more than 900 hours. A consumer advocacy group wants to test this claim. They obtained a simple random sample of 61 bulbs and timed how long they took to burn out. They obtained a sample mean of 907.5 hours with a standard deviation of 16.5 hours. It’s your job to test the claim at the 5% significance level and determine if the manufacturer is...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT