Question

In: Statistics and Probability

A manufacturer claims that the average tread life of a premium tire exceeds the average tread...

A manufacturer claims that the average tread life of a premium tire exceeds the average tread life of economy tire of the same size by at least 5000 miles. To test this claim, 50 pieces of each type of tires were tested under similar conditions. The premium tire had an average tread life of 43000 miles with a sample standard deviation of 2300, while economy tire had an average tread life of 37500 miles with a sample standard deviation of 1800. Test the manufacturer’s claim using a 0.05 level of significance. Calculate P-Value.

Solutions

Expert Solution

?????????:-

?????? ?????


Related Solutions

17. A tire manufacturer claims that the average life of a certain grade of tire is...
17. A tire manufacturer claims that the average life of a certain grade of tire is 50,000 miles or more when used under normal driving conditions. A random sample of 20 tires is selected and tested and the sample mean is 49,650 miles. Assume the population of the lives is to be normal with standard deviation of 5,000 miles. At the 5% significance level, the manufacturer’s claim is tested. What is the decision rule in this test? A. Reject H0...
A tire manufacturer believes that the tread life of its snow tires can be described by...
A tire manufacturer believes that the tread life of its snow tires can be described by Normal model with a mean of 32,000 miles and a standard deviation of 2500 miles. a). If you buy a set of these tires, would it be reasonable for you to hope that they'll last 40,000 miles? Explain. b). Approximately what fraction of these tires can be expected to last less that 30,000 miles? c). Approximately what fraction of these tires can be expected...
tire manufacturer claims that the life span of its tires is 60,000 miles. Assume the life spans of the tire are normally distributed.
tire manufacturer claims that the life span of its tires is 60,000 miles. Assume the life spans of the tire are normally distributed. You selected 25 tires at random and tested them. The mean life span of the sample is 58,800 miles. The tires had a sample standard deviation, s = 600. Use the .10 level of significance. Which distribution would be indicated? Explain why you chose that distribution. Construct a confidence interval for the mean using the above data....
Suppose you work at a large tire distribution center. The tires’ average tread life has been...
Suppose you work at a large tire distribution center. The tires’ average tread life has been 50,000 miles with a standard deviation of 5,000 miles. At the end of the year, the company can reevaluate their supply contract. There are four supply options for the next contract: the current supplier or one of three competitors. The current supplier produces tires with an average tread life of 50,000 miles with a standard deviation of 5,000 miles. Competitor A claims to produce...
A tire manufacturer claims that the life span of its tires is 52,000 miles. Assume the...
A tire manufacturer claims that the life span of its tires is 52,000 miles. Assume the life spans of the tire are normally distributed. You selected 16 tires at random and tested them. The mean life span of the sample is 50,802 miles. The tires had a population standard deviation, σ = 800. Use the .05 level of significance. a) Which distribution would be indicated? b) Explain why you chose that distribution. c) Construct a confidence interval for the mean...
the tread of life of a particular brand of tire is a random variable best described...
the tread of life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 70000 miles and a standard deviation of 9300 miles. what warranty should the company use if they want 89.25% of the tires to outlast the warranty? round to the nearest integer. (show work please)
The mean tread life of a manufacturer's best selling tire is known to be 22,560 miles....
The mean tread life of a manufacturer's best selling tire is known to be 22,560 miles. Because the distribution of individual tire life is positively skewed, it cannot be assumed to be normal. R&D has come up with a new rubber additive that they suspect will increase mean tire life without affecting variability of tire life. A sample of 36 tires with the new additive has a sample mean tread life of 24,470 miles; the sample based estimate of the...
.Tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires of...
.Tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires of each tread type were driven for 1000 miles on each of 9 different cars. The mileages, in miles per gallon, were as follows. Test whether the mean mileage is the same for both types of tread. (ANOVA test) Car 1 2 3 4 5 6 7 8 9 Tread A 24.7 22.5 24.0 26.9 22.5 23.5 22.7 19.7 27.5 Tread B 20.3 19.0 22.5...
A tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires...
A tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires of each tread type were driven for 1000 miles on each of 9 different cars. The mileages, in miles per gallon, were as follows: Car Tread A Tread B 1 24.7 20.4 2 22.6 19.0 3 23.9 22.4 4 26.8 23.0 5 22.4 20.8 6 23.4 23.5 7 22.6 21.3 8 19.7 18.1 9 27.3 25.8 (a) Construct an 80% confidence interval for the...
A tire manufacturer claims its tires will last for 80,000 miles on average when properly maintained....
A tire manufacturer claims its tires will last for 80,000 miles on average when properly maintained. To investigate this claim, a retail tire store has surveyed 49 recent customers of that particular tire and determined those tires lasted for an average of 77,470 miles. The population standard deviation is known to be 7,700 miles. Compute the value of the appropriate test statistic to test this claim. Enter your answer as a decimal rounded to two places. Indicate a negative value...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT