In: Chemistry
(3) You have a 5 M sucrose stock solution and need 90 mL of the three following solutions for your experiment: 0.5 M, 0.05 M, and 0.005 M sucrose, respectively. How will you prepare the 3 sucrose solutions you need? You can use a diagram to explain your answer.
Preparation of 90 mL of 0.5 M sucrose solution :
According to law of dilution MV = M'V'
Where M = Molarity of stock = 5 M
V = Volume of the stock = ?
M' = Molarity of dilute solution = 0.5 M
V' = Volume of the dilute solution = 90 mL
Plug the values we get , V' = MV /M'
= 9 mL
So take 9 mL of the stock solution and diluted it to 90 mL by using distilled water
Preparation of 90 mL of 0.05 M sucrose solution :
According to law of dilution MV = M'V'
Where M = Molarity of stock = 5 M
V = Volume of the stock = ?
M' = Molarity of dilute solution = 0.05 M
V' = Volume of the dilute solution = 90 mL
Plug the values we get , V' = MV /M'
= 0.9 mL
So take 0.9 mL of the stock solution and diluted it to 90 mL by using distilled water
Preparation of 90 mL of 0.005 M sucrose solution :
According to law of dilution MV = M'V'
Where M = Molarity of stock = 5 M
V = Volume of the stock = ?
M' = Molarity of dilute solution = 0.005 M
V' = Volume of the dilute solution = 90 mL
Plug the values we get , V' = MV /M'
= 0.09 mL
So take 0.09 mL of the stock solution and diluted it to 90 mL by using distilled water