Question

describe how you would prepare 1.25L of a 0.025 M sucrose solution from a stock solution with concentration of 5.00 M.

Answer 1

According to law of dilution MV = M'V'

Where

M = Molarity of stock solution = 5.00 M

V = Volume of stock solution taken = ?

M' = Molarity of dilute solution = 0.025 M

V' = Volume of the dilute solution = 1.25 L

Plug the values we get V = M'V' / M

                                       = ( 0.025 x 1.25 ) / 5.00

                                      = 6.25x10 ^-3 L

                                      = 6.25 mL                       Since 1L = 10 ³ mL

So exactly take 6.25 mL of 5.00 M stock solution of sucrose in a beaker and make up the solution untill we get 1.25 L with distilled water, we get the required solution,