Question

1. I give you 100mL of a 3 M aqueous glucose stock solution. I need you to dilute it to make 100mL of a solution that is 0.03M. To accomplish this task, you have 2 additional 100 mL graduated cylinders and however much distilled water you need. The graduated cylinders are not really accurate at measuring any volume less than 5mL. (10 pts)
2. 1. How would you dilute 3M stock solution into 0.03 M solution? Explain strategy.

2. Show your calculations:  

Answer 1

ANSWER )

PLEASE GO THROUGH RED BOLD HIGHLIGHTED ANSWER. THE BLACK BOLD  IS JUST AN EXPLANATION

M1 X V1 = M2 X V2

M1 = 3 M (STOCK SOLUTION CONCENTRATION)

M2 = 0.03M ( REQUIRED SOLUTION CONCENTRATION)

V2 = 100 ( REQUIRED VOLUME )

V1 = (STOCK VOLUME)

APPLYING THIS FORMULA 3 X V1 = 0.03 X 100

= V1 = 0.03 X 100/ 3 = 1 ML

SINCE WE DON'T HAVE CYLINDER TO MEASURE 1 ML

SO WE WILL INCREASE THE REQUIRED VOLUME ( V2 ) TO 1000 ML ACCORDINGLY WE WILL CALCULATE AGAIN

M1 X V1 = M2 X V2

3 X V1 = 0.03 X 1000

V1 = 10ML

10ML CAN BE MEASURED FROM MEASURING CYLINDER

SO NOW FROM 3 M AQUEOUS GLUCOSE STOCK SOLUTION WE WILL TAKE 10 ML AND ADD UP IN 990 ML OF WATER ( 100 ML WATER X 9 TIMES AND 90 ML WATER X 1 TIME )

THIS WILL MAKE 1000 ML OF 0.03 M GLUCOSE SOLUTION

NOW MEASURE 100 ML OF SOLUTION OF 0.03M GLUCOSE SOLUTION AS YOU REQUIRED ACCORDING TO QUESTION

NOTE WE COULD HAVE INCREASE OUR V2 VOLUME TO 500 BUT IT MAY LEAD TO DISCREPANCY AND NOT ACCURATELY MEASURE SO WE HAVE TAKEN 1000ML