Identify the compound with the lowest standard free energy of formation. O3(g) N2(g) It is hard...

Identify the compound with the lowest standard free energy of formation. O3(g) N2(g) It is hard to determine. NaCl(s) NO(g)

Expert Solution

Answer: NaCl(s)

EXPLAINATION: Standard free energy of formation is the change in the Gibbs free energy when one mole of a substance is formed from its respective constituent elements at standard condition of temperature and pressure (1 bar and 25°C).

N₂(g) is the elemental form of nitrogen gas. So, the free energy formation of N₂(g) = 0. (All elements in their natural elemental state has 0 standard free energy of formation)

O₃(g) has standard free energy of formation value = 163.2 kJ/mol

NO(g) has standard free energy of formation value = 86.55 kJ/mol

NaCl(s) has standard free energy of formation value = -384.138 kJ/mol.

So, the lowest standard free energy of formation is for NaCl(s).

Generally, ionic solids have very low value of standard free energy of formation than any gaseous compounds. Most ionic compounds has high negative value of standard free energy of formation.

queen_honey_blossom answered 3 years ago

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