In: Statistics and Probability
Forma a 95% confidence interval on the mean pouring temperature for iron castings if a sample of size 25 yielded a mean of 2560 and a standard deviation (s) of 20.
Solution :
Given that,
= 2560
s = 20
n = 25
Degrees of freedom = df = n - 1 = 25 - 1 = 24
a ) At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/
2 = 0.05 / 2 = 0.025
t
/2,df = t0.025,24 =2.064
Margin of error = E = t/2,df
* (s /
n)
= 2.064* (20 /
25) = 8.256
The 95% confidence interval is,
- E <
<
+ E
2560 - 8.256<
< 2560 + 8.256
2551.744 <
< 2568.256
(2551.744 , 2568.256)