In: Statistics and Probability
The 95% confidence interval for the mean, calculated from a sample of size n = 25 is 2.233163 ≤ μ ≤ 3.966837 . Determine the sample mean X ¯ = (round to the first decimal place). Assuming that the data is normally distributed, determine the sample standard deviation s = (round to the first decimal place)
Lower value from confidence interval = 2.233163
Upper value from confidence interval = 3.966837
Now we find margin of error (E)
We know formula of the margin of error from Confidence interval.
C = level of confidence = 0.950 ( We converted 95 % in to decimal )
df = degree of freedom = n - 1 = 25 - 1 = 24
t(n-1 , c ) = t critical value
We look for df = 24 and c = 0.950
We look for row headed 24 and column headed 0.950
t(24 , 0.950 ) = 2.064
We use formula
Now we solve this equation for s
Round value of s up to 1 decimal place
s = 2.1
Final answer :-
s = 2.1
I hope this wil help you :)