For the equation ch4 + 2h2s = cs2 + 4h2 what is the oxidation state for...

For the equation ch4 + 2h2s = cs2 + 4h2 what is the oxidation state for C, H, and S?

Expert Solution

For the equation CH₄ + 2H₂S ------> CS₂ + H₂

The oxidation state for H

The oxidation state of H in H₂S is +1, it gets electrons and became more negative in H_2. H₂ is an element with oxidation state 0

The oxidation state for C

Carbon has an Oxidation number of -4 in CH₄. The hydrogen has +1 for each one of them, since there are 4 of them; the carbon has to be -4 to counter out the hydrogen positive charges. The carbon inside CS₂ is at an oxidation state of +4, being up against 2 S, each S has oxidation number -2

The oxidation state for S

In H₂S the oxidation state of S is -1, it gains electrons and became more negative in CS₂ and the oxidation state of S became -2.

queen_honey_blossom answered 2 years ago

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