What is the oxidation state of the phosphorus atom in phosphite, PO33-?

Expert Solution

Phosphite ion is PO₃^3-

It constitutes of phosphorus P and oxygen O and the overall charge or oxidation number of phosphite ion is -3

Oxidation number of O₃ is 3*(-2) = -6. Oxygen exists in -2 oxidation state.

So, P + (-6) = -3

On solving P = +3

So, oxidation state of phosphorus in phosphite ion is +3

queen_honey_blossom answered 2 years ago

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