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Hydrogen peroxide, H2O2, decomposes to water and oxygen gas. What is the oxidation state (oxidation number)...

Hydrogen peroxide, H2O2, decomposes to water and oxygen gas. What is the oxidation state (oxidation number) for oxygen in hydrogen perioxide?

+1
+2
-1
-2

0

What volume of 0.10 M CH3CO2H is required to react with 0.50 moles of NaHCO3 in the following reaction?

The balanced equation is:

CH3CO2H(aq) + NaHCO3(s)  → CO2(g) + H2O(l) + NaCH3CO2(aq)

1.0 L
2.0 L
0.50 L
5.0 L
0.20 L

If 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric acid solution?

Start by balancing the equation for the reaction:  

H3PO4(aq) + NaOH(aq)  → Na3PO4(aq) + H2O(l)

0.472 M
1.42 M
0.157 M
0.282 M
0.0667 M

Solutions

Expert Solution

1. 2H2O2(aq) -------------->2H2O(l)   + O2(g)

in H2O2 oxygen oxidation state is -1.

H-O--O-H peroxy bond. In peroxides oxygen oxidation state is -1

-1>>>>answer

2.

CH3CO2H(aq) + NaHCO3(s)  → CO2(g) + H2O(l) + NaCH3CO2(aq)

1 mole of NaHCO3 react with 1 mole of CH3CO2H

0.5 moles of NaHCO3 react with 0.5 moles of Ch3CO2H

no of moles of CH3CO2H   = molarity * volume in L

0.5                                       = 0.1* volume in L

volume in L                           = 0.5/0.1 = 5 L

5.0L >>>>>answer

3.

H3PO4(aq) + 3NaOH(aq)  → Na3PO4(aq) + 3H2O(l)

1 mole         3 moles

H3PO4                                                        NaOH

M1 =                                                          M2 = 0.2M

V1 = 10ml                                                  V2 = 23.6ml

n1 = 1                                                        n2 = 3

                 M1V1/n1    =    M2V2/n2

                       M1         =   M2V2n1/V1n2

                                      =   0.2*23.6*1/10*3    = 0.157M

The concentration of the phosphoric acid solution is 0.157M

0.157M >>>>.answer


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