In: Chemistry
Determine the oxidation state for each of the elements below.
The oxidation state of |
... |
iodine |
... |
in |
... |
diiodine pentoxide |
... |
is |
... |
___ . |
The oxidation state of |
sulfur |
in |
sulfur trioxide |
is |
__ |
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The oxidation state of |
bromine |
in |
bromine trifluoride |
is |
___. |
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1)
Oxidation number of O = -2
lets the oxidation number of I be x
use:
5* oxidation number (O) + 2* oxidation number (I) = net charge
5*(-2)+2* x = 0
-10 + 2 * x = 0
x = 5
So oxidation number of I = +5
Answer: +5
2)
Oxidation number of O = -2
lets the oxidation number of S be x
use:
3* oxidation number (O) + 1* oxidation number (S) = net charge
3*(-2)+1* x = 0
-6 + 1 * x = 0
x = 6
So oxidation number of S = +6
Answer: +6
3)
Oxidation number of F = -1
lets the oxidation number of Br be x
use:
3* oxidation number (F) + 1* oxidation number (Br) = net charge
3*(-1)+1* x = 0
-3 + 1 * x = 0
x = 3
So oxidation number of Br = +3
Answer: +3