In: Chemistry
Consider the following four equilibria at 298 K:
CH4(g) + 4S(s) ⇌ CS2(g) + 2H2S(g) Kp = 9.5 × 10-10
S(s) + F2(g) ⇌ SF2(g) Kp = 1.6 × 1053
C2F2(g) + 4H2(g) ⇌ 2CH4(g) + F2(g) Kp = 1.5 × 1020
S(s) + H2(g) ⇌ H2S(g) Kp = 7.2 × 105
Question 1 What is Kp at 298 K for the following equilibrium? 2CH4(g) + SF2(g) ⇌ C2F2(g) + H2S(g) + 3H2(g)
Question 2 What is Kp at 298 K for the following equilibrium? CS2(g) + 4H2(g) ⇌ CH4(g) + 2H2S(g)
Question 3 What is Kp at 298 K for the following equilibrium? C2F2(g) + 5S(s) ⇌ 2CS2(g) + SF2(g)
Question 1 What is Kp at 298 K for the following equilibrium?
2CH4(g) + SF2(g) < ---- > C2F2(g) + H2S(g) + 3H2(g)
Solution :- we want SF2 on reactant side so reverse equation 2
C2F2 need to be on product side so reverse equation 3
New equations are as follows
SF2(g) < ------ > S(s) + F2(g) Kp = 1/1.6 × 10^53
2CH4(g) + F2(g) < ----- > C2F2(g) + 4H2(g) Kp = 1/1.5 × 10^20
S(s) + H2(g) < ---- > H2S(g) Kp = 7.2 × 10^5
Adding these equations by cancelling the similar species on opposite sides we get
2CH4(g) + SF2(g) < ---- > C2F2(g) + H2S(g) + 3H2(g)
Kp = (1/1.6*10^53)*(1/1.5*10^20)* 7.5*10^5
Kp = 3.13*10^-68
Question 2 What is Kp at 298 K for the following equilibrium? CS2(g) + 4H2(g) < ---- > CH4(g) + 2H2S(g)
Solution :-
Need CS2 on reactant side and CH4 and H2S on product side
So reverse equation 1
Use equation 4 and multiply it by 4
CS2(g) + 2H2S(g) < ------ > CH4(g) + 4S(s) Kp = 1/9.5 × 10^-10
4S(s) + 4H2(g) < ---- > 4H2S(g) Kp = (7.2 × 10^5)^4
By adding these equations we get
CS2(g) + 4H2(g) < ---- > CH4(g) + 2H2S(g)
Kp = (1/9.5*10^-10) * (7.2*10^5)4
Kp = 2.83*10^32
Question 3 What is Kp at 298 K for the following equilibrium? C2F2(g) + 5S(s) ⇌ 2CS2(g) + SF2(g)
Solution :-
We want C2F2 on reactant side so keep equation 3 as it is
Need SF2 on product side so keep equation 2 as it
Need CS2 on product side so need equation 1 as it and multiply by 2
Reverese equation 4 and multiply by 4
New equations are
2CH4(g) + 8S(s) < ---- > 2CS2(g) + 4H2S(g) Kp = (9.5 × 10^-10)^2
S(s) + F2(g) < ---- > SF2(g) Kp = 1.6 × 10^53
C2F2(g) + 4H2(g) < ---- > 2CH4(g) + F2(g) Kp = 1.5 × 10^20
4H2S(g) < ----- > 4S(s) + 4H2(g) Kp = (1/7.2 × 10^5)^4
By adding all these equations we get
C2F2(g) + 5S(s) < ---- > 2CS2(g) + SF2(g)
Kp = (9.5*10^-10)^2 * 1.6*10^53 *1.5*10^20 * (1/7.2*10^5)^4
= 8.06*10^31