Question

In: Statistics and Probability

Consider the following regression results based on 20 observations. [You may find it useful to reference...

Consider the following regression results based on 20 observations. [You may find it useful to reference the t table.]

Coefficients Standard Error t Stat p-value
Intercept 31.4333 4.5131 6.965 0.000
x1 0.1987 0.1470 1.352 0.193

a-1. Choose the hypotheses to determine if the intercept differs from zero.

  • H0: β0 ≤ 0; HA: β0 > 0

  • H0: β0 ≥ 0; HA: β0 < 0

  • H0: β0 = 0; HA: β0 ≠ 0


a-2. At the 5% significance level, what is the conclusion to the hypothesis test? Does the intercept differ from zero?

  • Reject H0; the intercept is greater than zero.

  • Reject H0; the intercept differs from zero.

  • Do not reject H0; the intercept is greater than zero.

  • Do not reject H0; the intercept differs from zero.

b-1. Construct the 95% confidence interval for the slope coefficient. (Negative values should be indicated by a minus sign. Round "tα/2,df" value to 3 decimal places and final answers to 2 decimal places.)


b-2. At the 5% significance level, can we conclude the slope differs from zero?

  • Yes, since the interval contains zero.

  • Yes, since the interval does not contain zero.

  • No, since the interval contains zero.

  • No, since the interval does not contain zero.

Solutions

Expert Solution

A-1)

A-2)

P VALUE FOR INTERCEPT = 0.000

P VALUE < 0.05,REJECT Ho

...

b-1)

confidence interval for slope                      
                      
n =   20                  
alpha,α =    0.05                  
estimated slope=   0.1987                  
std error =    0.147                  
                      
Df = n-2 =   18                  
t critical value =    2.101   [excel function: =t.inv.2t(α,df) ]              
                      
margin of error ,E = t*std error =    2.1009   *   0.147   =   0.3088  
                      
95%   confidence interval is ß1 ± E                   
lower bound = estimated slope - margin of error =    0.1987   -   0.3088   =   -0.11  
upper bound = estimated slope + margin of error =    0.1987   +   0.3088   =   0.51  
CI (-0.11 , 0.51 )

b-2)

...............

Please revert back in case of any doubt.

Please upvote. Thanks in advance.


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