In: Statistics and Probability
A multinomial experiment produced the following results: (You may find it useful to reference the appropriate table: chi-square table or F table)
A multinomial experiment produced the following results: (You may find it useful to reference the appropriate table: chi-square table or F table)
Category | 1 | 2 | 3 | 4 | 5 |
Frequency | 64 | 37 | 67 | 59 | 57 |
a. Choose the appropriate alternative hypothesis to test if the population proportions differ.
All population proportions differ from 0.20.
Not all population proportions are equal to 0.20.
b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)
c. Find the p-value.
p-value < 0.01
d. Can we conclude at the 10% significance level that the population proportions are not equal?
No, since the p-value is less than the significance level.
Yes, since the p-value is less than the significance level.
No, since the p-value is more than the significance level.
Yes, since the p-value is more than the significance level.
Answer: A multinomial experiment produced the following results:
Solution:
Proportion p = 1/5 = 0.20
a) The null and alternative hypothesis test:
Ho: p1 = p2 = p3 = p4 = p5 = 0.20
Ha: Not all population proportions are equal to 0.20.
b) From the given data we used chi square test statistic χ2 at α = 0.05 significance level.
n = 64+37+67+59+57
n = 284
Expected frequency = n*p
Expected frequency = 284 * 0.20
Expected frequency = 56.8
Category | Observed (O) | Expected (E) | (O-E)^2/E |
1 | 64 | 56.8 | 0.9127 |
2 | 37 | 56.8 | 6.9021 |
3 | 67 | 56.8 | 1.8317 |
4 | 59 | 56.8 | 0.0852 |
5 | 57 | 56.8 | 0.0007 |
Total | 284 | 284 | 9.7324 |
Test statistic χ2 = Σ(O-E)^2/E
Test statistic χ2 = 9.732
c) P-value:
Degree of freedom, df = k-1
df = 5 - 1 = 4
P-Value is .0452
Since, P-Value is 0.0452.
The first option is correct.
0.025 < P-value (0.0452) < 0.05
d) Conclusion:
Since, P-value (0.0452) < α (0.10)
Reject the null hypothesis Ho. There is sufficient evidence to conclude that the not all population proportions are equal to 0.20.