In: Chemistry
What is the minimum amount of 5.6 M H2SO4 necessary to produce 24.7 g of H2 (g) according to the following reaction? 2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)
we have the Balanced chemical equation as:
2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)
Molar mass of H2 = 2.016 g/mol
mass of H2 = 24.7 g
we have below equation to be used:
number of mol of H2,
n = mass of H2/molar mass of H2
=(24.7 g)/(2.016 g/mol)
= 12.25 mol
From balanced chemical reaction, we see that
when 3 mol of H2 forms, 3 mol of H2SO4 reacts
mol of H2SO4 reacted = (3/3)* moles of H2
= (3/3)*12.252
= 12.25 mol
This is number of moles of H2SO4
we have below equation to be used:
M = number of mol / volume in L
5.6 = 12.25/ volume in L
volume = 2.19 L
Answer: 2.19 L