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Kc for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I2(g) ⇌...

K_c for the reaction of hydrogen and iodine to produce hydrogen iodide.

H₂(g) + I₂(g) ⇌ 2HI(g)

is 54.3 at 430°C. Calculate the equilibrium concentrations of H₂, I₂, and HI at 430°C if the initial concentrations are [H₂] = [I₂] = 0 M, and [HI] = 0.547 M.

[H₂]=

[I₂]=

[HI]=

Expert Solution

H₂(g) + I₂(g) ⇌ 2HI(g)

I 0 0 0.547

C +x +x -2x

E +x +x 0.547-2x

Kc = [HI]^2/[H2][I2]

54.3 = (0.547-2x)^2/x*x

54.3 = (0.547-2x/x)^2

7.37 = 0.547-2x/x

7.37x = 0.547-2x

x = 0.0584

[H2] = x = 0.0584M

[I2] = x = 0.0584M

[HI] = 0.547-2x = 0.547-2*0.0584 = 0.43M

queen_honey_blossom answered 1 year ago

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