In: Statistics and Probability
The average cost of a one-bedroom apartment in a town is $650 per month. What is the probability of randomly selecting a sample of 50 one-bedroom apartments in this town and getting a sample mean of less than $630 if the population standard deviation is $100? (Round the values of z to 2 decimal places. Round your answer to 4 decimal places.)
Solution :
Given that ,
mean = = $650
standard deviation = = $100
n = 50
= 650
= / n = 100 / 50=14.1421
P( <$630 ) = P[( - ) / < (630-650) / 14.1421]
= P(z <-1.41 )
Using z table
= 0.0793
probability=0.0793