In: Statistics and Probability
The average cost of a one-bedroom apartment in a town is $650 per month. What is the probability of randomly selecting a sample of 50 one-bedroom apartments in this town and getting a sample mean of less than $630 if the population standard deviation is $100? (Round the values of z to 2 decimal places. Round your answer to 4 decimal places.)
Solution :
Given that ,
mean = 
 = $650
standard deviation = 
 = $100
n = 50

= 650

=
  /
n = 100 / 
50=14.1421
P(
<$630 ) = P[(
- 
) / 
< (630-650) / 14.1421]
= P(z <-1.41 )
Using z table
= 0.0793
probability=0.0793