Question

Titration for Acetic Acid in Vinegar – Lab Report Assistant

Exercise 1: Determining the Concentration of Acetic Acid

Data Table 1. NaOH Titration Volume

	Initial NaOH Volume (mL)	Final NaOH Volume (mL)	Total volume of NaOH used (mL)
Trial 1	5.2	2.3	2.9
Trial 2	6.2	3.9	2.9
Trial 3	7.2	4.9	2.9
	Average Volume of NaOH Used (mL) : 2.9

Data Table 2. Concentration of CH₃COOH in Vinegar

Average volume of NaOH used (mL)	Concentration CH3COOH in vinegar (mol/L)	% CH3COOH in vinegar
0.0029		1.74%

Questions:

If the manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid, what would the percent error between your result and the manufacturer’s statement be? Show your work.

Answer 1

To calculate the concentration of Acetic Acid in Vinegar,we must know thw volume of Vinegar that was taken to titrate with NaOH(you must know that from your Lab Results).

Step-I:

You can then use the balanced chemical equation of the reaction between NaOH and AcOH which tells that these two will react in 1:1 ratio,

Step-II:

then calculate the no of moles of NaOH required which is the strength of NaOH in Molarity(mol/L) [again not mentioned] multiplied by 0.0029L NaOH .

Step -III:

This no. of moles of NaOH=No. of moles of AcOH in Vinegar

So from here we get the no of moles of Acetic Acid present in Vinegar,now

Step-IV:

Do the Math!

No of moles of Acetic Acid/Volume ofVinegar taken in Litres=Strength of Acetic Acid in Molarity..

Answer of the Question-

Hence,% Error=%.