Question

In: Chemistry

Calculate the weight % of acetic acid in the vinegar. Calculate your percent error. For this...

Calculate the weight % of acetic acid in the vinegar. Calculate your percent error. For this calculation, assume that the density of vinegar is 1.01g/mL.

0.8488 Molarity of acetic acid in my experiment.

I'm a little confused-if you solve it can you be sure to specify what the conversion factors are in the calculations. Thank you!

Solutions

Expert Solution

Density of vinegar = 1.01g/ml

assume volume of vinegar = 1L = 1000ml

mass of vinegar = density * volume in ml

                        = 1.01*1000 = 1010gm

molarity of acetic acid = 0.8488M

assume volume of acetiv acid = 1L

no of moles of acetic acid = molarity *volume in L

                                       = 0.8488*1 = 0.8488moles

mass of acetic acid        = no of moles * G.M.Wt

                                  = 0.8488*60 = 50.928gm

mass percentage of acetic acid = mass of acetic acid*100/mass of vinegar

                                                 = 50.928*100/1010

                                                  = 5.04%

percentage error = Actual mass- calculated mass*100/actual mass

But actual mass not given


Related Solutions

Deterime the % of Acetic Acid in vinegar in your kitchen. Show how to determine it...
Deterime the % of Acetic Acid in vinegar in your kitchen. Show how to determine it in words and make up random numbers to calculate it also. Determine the purity of an Aluminum can. In words how would you determine the purity? Also, make up random numbers to calculate how to find the purity of an Aluminum can. Identifiy the ions present in a sample possibly containing Ag+ Pb2+ Br2+ Na+ Ca2+. Construct a flowchart using these ions.
Students performing vinegar analyses made several mistakes in their experiments. Explain in detail how each error below will affect the final result (% weight of acetic acid in vinegar) of each student's experiment.
Students performing vinegar analyses made several mistakes in their experiments. Explain in detail how each error below will affect the final result (% weight of acetic acid in vinegar) of each student's experiment. Show all steps of logic followed in analyzing the effects of the mistake (remember that the experiment had two parts): 1.Student A used a wet beaker to transfer the NaOH solution to be standardized from its original container to the buret. 2.Student B did not fill the...
The distinctive odor of vinegar is due to acetic acid, HC2H3O2. Acetic acid reacts with sodium...
The distinctive odor of vinegar is due to acetic acid, HC2H3O2. Acetic acid reacts with sodium hydroxide in the following fashion: HC2H3O2(aq) + NaOH(aq)-> H2O(l) + NaC2H3O2(aq). If 2.52 mL of vinegar requires 34.9 mL of 0.1031 M (molarity) NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.00 qt sample of this vinegar? (1 L = 1.0567 qt)
Calculate the percent ionization of 1.50 M aqueous acetic acid solution. For acetic acid, Ka =...
Calculate the percent ionization of 1.50 M aqueous acetic acid solution. For acetic acid, Ka = 1.8 × 10−5 . (a) 2.71% (b) 3.55% (c) 1.78% (d) 0.35% (e) None of the above
1. Vinegar consists of acetic acid, CH3COOH, and water. Write out the equilibrium expression for acetic...
1. Vinegar consists of acetic acid, CH3COOH, and water. Write out the equilibrium expression for acetic acid reacting with water. 2. Citric acid, H3C6H5O7, contributes to the acidity of many foods. Write out the equilibrium expression for citric acid reacting with water to lose one acidic proton.
Sally chemist is attempting to determine the mass % of acetic acid in vinegar. Below is...
Sally chemist is attempting to determine the mass % of acetic acid in vinegar. Below is an excerpt from her lab book: A. Prepared vinegar analyte 25.0 mL vinegar mass of vinegar 25.20 grams added 75.0 mL H2O added 2 drops phenolphthalein temperature: 27.0 oC manufacturer's mass % acetic acid = 3.5 % B. Prepared burette filled with standardized NaOH solution 0.201 M C. Titration initial burette reading: 5.12 mL final burette reading: 78.67 mL solution is light pink 1....
A) Calculate the percent ionization of a 0.546 M solution of acetic acid. % Ionization =...
A) Calculate the percent ionization of a 0.546 M solution of acetic acid. % Ionization = ______ % (No Ka value was given) B) In the laboratory a student measures the percent ionization of a 0.438 M solution of nitrous acid to be 3.31 %. Calculate value of Ka from this experimental data.  Ka = ______ C) Calculate the percent ionization of a 0.390 M solution of nitrous acid. % Ionization = ______ % (No Ka value was given)
Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a...
Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution according to the equation H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2 H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2 If you require 33.38 mL of 0.1936...
A.) Vinegar is a solution of acetic acid, HCH3COO, in water. Because only the first hydrogen...
A.) Vinegar is a solution of acetic acid, HCH3COO, in water. Because only the first hydrogen atom ionizes, acetic acid is a monoprotic acid. A 25.00 mL sample of vinegar was analyzed using 0.002450 M NaOH solution. The analysis required 8.93 mL of the sodium hydroxide solution. Write a balanced equation for the reaction of acetic acid with sodium hydroxide. How many mg of acid are present in the sample of vinegar? What is the mass percent acetic acid in...
A food chemist determines the concentration of acetic acid in a sample of apple cider vinegar...
A food chemist determines the concentration of acetic acid in a sample of apple cider vinegar by acid-base titration. What is the concentration of acetic acid in the vinegar if the density of the sample is 1.01 g/ml, the titrant is 1.002M NaOH and the average volume of titrant required to titrate 25.00 mL subsamples of the vinegar is 20.78mL? Express your answer the way a food chemist probably would; *as percent by mass*
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT