In: Chemistry
Calculate the weight % of acetic acid in the vinegar. Calculate your percent error. For this calculation, assume that the density of vinegar is 1.01g/mL.
0.8488 Molarity of acetic acid in my experiment.
I'm a little confused-if you solve it can you be sure to specify what the conversion factors are in the calculations. Thank you!
Density of vinegar = 1.01g/ml
assume volume of vinegar = 1L = 1000ml
mass of vinegar = density * volume in ml
= 1.01*1000 = 1010gm
molarity of acetic acid = 0.8488M
assume volume of acetiv acid = 1L
no of moles of acetic acid = molarity *volume in L
= 0.8488*1 = 0.8488moles
mass of acetic acid = no of moles * G.M.Wt
= 0.8488*60 = 50.928gm
mass percentage of acetic acid = mass of acetic acid*100/mass of vinegar
= 50.928*100/1010
= 5.04%
percentage error = Actual mass- calculated mass*100/actual mass
But actual mass not given