Given the differential equation
y′′-3y′-4y=-2sin(2t), y(0)=-1, y′(0)=1
Apply the Laplace Transform and solve for Y
Y(s)=L{y}
Y(s)=
L(y′)=sY(s)-y(0)and...
Given the differential equation
y''+y'+2y=0, y(0)=−1, y'(0)=2y′′+y′+2y=0, y(0)=-1, y′(0)=2
Apply the Laplace Transform and solve for Y(s)=L{y}Y(s)=L{y}. You
do not need to actually find the solution to the differential
equation.
using the Laplace transform solve the IVP
y'' +4y= 3sin(t) y(0) =1 , y'(0) = - 1 , i am stuck on the
partial fraction decomposition step. please explain the
decomposition clearly.