In: Statistics and Probability
The credit scores for 12 randomly selected adults who are considered high risk borrowers before and two years after they attend a personal finance seminar are given below.
Credit Score | ||
Adult | Before Seminar | After Seminar |
1 | 608 | 646 |
2 | 620 | 692 |
3 | 610 | 715 |
4 | 650 | 669 |
5 | 640 | 725 |
6 | 680 | 786 |
7 | 655 | 700 |
8 | 602 | 650 |
9 | 644 | 660 |
10 | 656 | 650 |
11 | 632 | 680 |
12 | 664 | 702 |
You will run a significance test to check if there is enough evidence to support the claim that the personal finance seminar helps adults increase their credit scores.
You’ll use α = 0.01 for significance test.
Result:
You will run a significance test to check if there is enough evidence to support the claim that the personal finance seminar helps adults increase their credit scores.
You’ll use α = 0.01 for significance test.
Write out the null and alternative hypothesis associated with the research question.
Let = mean of difference( before-after)
Ho: µd=0 H1: µd < 0
This is a lower tail test.
What type of statistical test will you use to answer the proposed research question? (Note: Is this a z-test or a t-test for independent or dependent samples)
t-test for dependent samples ( data are paired)
What is the critical value at the 0.01 level of significance? Be sure and include whether this critical value is a z or t value and, if appropriate, include the degrees of freedom associated with this statistical test.
DF= 12-1=1
Critical t at 0.01 level of significance = -2.7181
Reject Ho is calculated t > -2.7181
What is the standardized test statistic?
test statistic = -5.0731
At 0.01 significance level what decision should be made about the null hypothesis? In other words, should you reject or retain the null hypothesis?
Since test statistic = -5.0731 is less than critical t value -2.7181, we reject the null hypothesis.
Provide a brief conclusion regarding your findings.
There is enough evidence to support the claim that the personal finance seminar helps adults increase their credit scores.
Show your excel output (Excel Addon PHStat used )
Paired t Test |
|
Data |
|
Hypothesized Mean Difference |
0 |
Level of significance |
0.01 |
Intermediate Calculations |
|
Sample Size |
12 |
DBar |
-51.1667 |
Degrees of Freedom |
11 |
SD |
34.9385 |
Standard Error |
10.0859 |
t Test Statistic |
-5.0731 |
Lower-Tail Test |
|
Lower Critical Value |
-2.7181 |
p-Value |
0.0002 |
Reject the null hypothesis |