Question
In: Statistics and Probability
A simple random sample of 800 elements generates a sample proportion of 0.70. Provide a 90%...
A simple random sample of 800 elements generates a sample proportion of 0.70.
Provide a 90% confidence interval for the population proportion. (round to two decimal places) [Answer , Answer]
Provide a 99% confidence interval for the population proportion. (round to two decimal places) [Answer , Answer]
Solutions
Expert Solution
Solution :
Given that,
Point estimate = sample proportion = 
= 0.70
1 -
= 1 - 0.70 = 0.3
Z
/2
= 1.645
Margin of error = E = Z
/ 2 * 
* (1 -
)) / n)
= 1.645 * (
= 0.03
A 90% confidence interval for population proportion p is ,
- E < p <
+ E
0.70 - 0.03 < p < 0.70 + 0.03
0.67 < p < 0.73
The 95% confidence interval for the population proportion p is : 0.67 , 0.73
Point estimate = sample proportion =
= 0.70
1 -
= 1 - 0.47 = 0.3
Z/2
= 2.576
Margin of error = E = Z
/ 2 *
* (1 -
)) / n)
= 2.576 * (
= 0.04
A 99% confidence interval for population proportion p is ,
- E < p <
+ E
0.70 - 0.04 < p < 0.70 + 0.04
0.66 < p < 0.74
The 99% confidence interval for the population proportion p is : 0.66 , 0.74
orchestra answered 2 years agoRelated Solutions
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