In: Economics
Kermit is considering purchasing a new computer system. The purchase price is $148165. Kermit will borrow one-fourth of the purchase price from a bank at 10 percent per year compounded annually. The loan is to be repaid using equal annual payments over a 3-year period. The computer system is expected to last 5 years and has a salvage value of $6692 at that time. Over the 5-year period, Kermit expects to pay a technician $20,000 per year to maintain the system but will save $66204 per year through increased efficiencies. Kermit uses a MARR of 12 percent to evaluate investments. What is the net present worth for this new computer system?
Working notes:
(1) Loan amount ($) = 148165 / 4 = 37041.25
(2) First cost (year 0) ($) = 148165 - 37041.25 = 111123.75
(3) Annual loan repayment, years 1-3 ($) = Loan amount / P/A(10%, 3) = 37041.25 / 2.4869 = 14894.55
(4) Net cash flow (NCF) ($) = Annual savings - Technician cost - Loan repayment = 66204 - 20000 - Loan repayment
= 46204 - Loan repayment
(5) NCF in year 5 will be higher by $6692 (salvage value).
(6) Net Present Worth (NPW) of NCF is computed as follows Note that PV Factor in year N = (1.12)-N.
Year | First Cost | Loan Repayment | NCF | PV Factor @12% | Discounted NCF |
0 | -111123.75 | -111123.75 | 1.0000 | -111123.75 | |
1 | 14894.55 | 31309.45 | 0.8929 | 27954.87 | |
2 | 14894.55 | 31309.45 | 0.7972 | 24959.70 | |
3 | 14894.55 | 31309.45 | 0.7118 | 22285.45 | |
4 | 0 | 46204 | 0.6355 | 29363.48 | |
5 | 0 | 52896 | 0.5674 | 30014.61 | |
NPW of NCF ($) = | 23454.35 |
Screenshot of formula: