In: Chemistry
What volume of 0.550 M barium hydroxide is required to neutralize 30.50 mL of 0.289 M
perchloric acid ?
Ba(OH)2 +2 HClO4 ----> Ba(ClO4)2 +2H2O
1 mole 2moles
Acid Base
M1 = 0.289M M2 =0.55M
V1 = 30.05ml V2 =
n1 = 2 n2 =1
M1V1 = M2V2
n1 n2
V2 = M1V1n2/n1M2 = 0.289*30.50 *1/2*0.55 = 8.01 ml