A converging lens has a focal length of 15 cm. If an object is
placed at a distance of 5 cm from the lens,
a. find the image position
d i = _____ cm (include sign +/-)
b. find the magnification
M = _____(include sign +/-)
c. characterize the resulting image.
________(real or virtual)
________(enlarged or reduced)
________(upright or inverted)
a) The focal length of a converging lens is 35 cm. An object is
placed 100 cm in front of the lens. Describe the image.
b) The focal length of a converging lens is 35 cm. An object is
placed 30 cm in front of the lens. Describe the image.
c) The focal length of a diverging lens is 35 cm. An object is
placed 100 cm in front of the lens. Describe the image.
d) The focal length of...
An object is placed 49 cm to the left of a converging lens of
focal length 21 cm. A diverging lens of focal length − 29 cm is
located 10.3 cm to the right of the first lens. (Consider the
lenses as thin lenses).
a) Where is the final image with respect to the second lens?
b)What is the linear magnification of the final image?
A diverging lens of focal length -12.5 cm is placed 40.0 cm from
a converging lens of unknown focal length. A 15.2 cm
tall erect object is placed 25.3 cm in front of the diverging lens
which is to produce an image on a screen that is twice the size of
the original object but inverted.
A)
Where should the screen be located to produce a clear image?
Give the distance from the converging lens to the screen in
cm.
B)...
A converging lens has a focal length of 21.1 cm.
(a) Locate the object if a real image is located at a distance
from the lens of 63.3 cm.
distance
cm
location
(b) Locate the object if a real image is located at a distance from
the lens of 105.5 cm.
distance
cm
location
(c) Locate the object if a virtual image is located at a distance
from the lens of -63.3 cm.
distance
cm
location
(d) Locate the object...
1. An object is 30 cm in front of a converging lens with a focal
length of 10 cm. Use ray tracing to
determine the location of the image. Is the image upright or
inverted? Is it real or virtual?
2. An object is 6.0 cm in front of a converging lens with a
focal length of 10 cm. Use ray tracing to
determine the location of the image. Is the image upright or
inverted? Is it real or virtual?...
An object is placed in front of a lens with focal length
f1, a second lens is placed at a distance of d from the
first lens and has focal length f2. Given that the
object has a height of h, find the height of the final image.
Set the focal length of the converging lens to 3.0 cm
and the object height 2.0 cm.
Start with the object distance at 8.0 cm. What happens
to the image position and image height as the object distance is
increased to 10.0 cm?
What happens to the image position and image height as the
object distance is decreased to 6.0 cm?
3. Next we’ll investigate images formed when the object is
closer to the lens than the focal point. Set...
A converging lens has a focal length of 9.0 cm. Locate the
images for the object distances of (a) 20.0 cm, (b) 10.0 cm, and
(c) 5.00 cm, if they exist. For each case, state whether the image
is real or virtual, upright or inverted, and find the
magnification.
A 1.00-cm-high object is placed 3.95 cm to the left of a
converging lens of focal length 9.00 cm. A diverging lens of focal
length −16.00 cm is 6.00 cm to the right of the converging lens.
Find the position and height of the final image.