A sky diver and her parachute system weigh a total of 800 N. She is falling...

A sky diver and her parachute system weigh a total of 800 N. She is falling vertically at v = 30 m/s when her parachute opens. At the instant that the parachute opens, the drag force acting vertically upward on the open chute is equal to F = 0.5v2.

Draw a FBD of the diver-parachute.

Draw a Kinetic diagram of the diver-parachute.

At the instant that the chute opens, calculate the vertical acceleration of the

sky diver.

Why does the sky diver

Expert Solution

-define the frame of refrence that you are using to describe his motion -describe his motion using newtons laws ----------------------------------------------------------------------- this is my final answer Phase A= skydiver jumps out of plane traveling at speed, accelerating phase B= traveling at terminal velocity, a=0 phase C = opens parachute; skydiver decelerates to new terminal velocity. Drag and air resistance are the same. The chute changes the profile of the falling object. The shape of the object changes, so the drag force will change as well. Phase D= skydiver continues at this speed till reaches ground phase C: drag and air resistance are the same. The chute changes the profile of the falling object. The shape of the object changes, so the drag force will change as well. During the entire fall, there are only two vertical forces, gravity and the drag force. The drag depends upon several aspects of the falling object. Phase A and B: downward force- gravity, upward force- air resistance phase C: downward force-gravity upward force= drag and air resistance

genius_generous answered 6 hours ago

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