In: Statistics and Probability
(1 point) Samples were collected from two ponds in the Bahamas to compare salinity values (in parts per thousand). Several samples were drawn at each site.
Pond 1: 37.36, 37.32, 37.45, 36.72, 37.03, 37.71, 37.01
Pond 2: 39.05, 38.66, 38.51, 38.89, 38.53
Use a 0.050.05 significance level to test the claim that the two
ponds have the same mean salinity value.
(a) The test statistic is
Solution:
We have
X | Y | X2 | Y2 |
37.16 | 39.05 | 1395.7696 | 1524.9025 |
37.32 | 38.66 | 1392.7824 | 1494.5956 |
37.45 | 38.51 | 1402.5025 | 1483.0201 |
36.72 | 38.89 | 1348.3584 | 1512.4321 |
37.03 | 38.53 | 1371.2209 | |
37.71 |
1422.0411 |
1484.5609 | |
37.01 | 1369.7401 | ||
=260.6 | =193.64 | =9702.418 | =7499.511 |
The sample mean is computed as